4x^2+96x-144=0

Solution for 4x^2+96x-144=0 equation:

4x^2+96x-144=0

a = 4; b = 96; c = -144;
Δ = b2-4ac
Δ = 962-4·4·(-144)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-48\sqrt{5}}{2*4}=\frac{-96-48\sqrt{5}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+48\sqrt{5}}{2*4}=\frac{-96+48\sqrt{5}}{8}
$